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x^2-11x=40=0
We move all terms to the left:
x^2-11x-(40)=0
a = 1; b = -11; c = -40;
Δ = b2-4ac
Δ = -112-4·1·(-40)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{281}}{2*1}=\frac{11-\sqrt{281}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{281}}{2*1}=\frac{11+\sqrt{281}}{2} $
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